Suppose an image is represented on a display screen by a square array containing 256 columns and 256 rows of pixels. If for each pixel, 3 bytes are required to encode the color and 8 bits to encode the intensity, how many byte- size memory cells are required to hold the entire picture?
Answer:
The byte-size memory cells that are required to hold the entire picture is 64KB.
According to this question,we were given the number of rows as (256).
The number of columns is been given as 256.
The required number of bytes to encode the color as 3.
To encode the intensity, number of bytes required is 8.
The number of pixels =( number of row * number of columns)
= (256 *256 )= 65536=(256∗256)=65536
The byte-size memory cells that are required to hold the entire picture
=(65536 *1024 )= 64KB=(65536∗1024)=64KB
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